A) T/4
B) \[\left( \frac{\sqrt{3}}{4} \right)T\]
C) \[\left( \frac{\sqrt{3}}{2} \right)T\]
D) \[\frac{T}{2}\]
Correct Answer: C
Solution :
The periodic time of pendulum in SHM is \[T=2\pi \sqrt{\frac{l}{g}}\] ?(i) where, \[l\] is length of pendulum and g is gravity. Effective gravity when lift accelerates upwards isYou need to login to perform this action.
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