A) methyl isocyanide
B) methyl cyanide
C) nitrobenzene
D) nitrotoluene
Correct Answer: A
Solution :
\[Isocyanide=\frac{\operatorname{Re}duction}{catalyst}s-a\min e\] \[Cyanide\xrightarrow[catalyst]{\operatorname{Re}duction}p-a\min e\] (Catalyst \[={{H}_{2}}/Ni\]or \[LiAl{{H}_{4}}\] or \[{{H}_{2}}/Na/{{C}_{2}}{{H}_{5}}OH\]or \[{{H}_{2}}/Pt\]) \[\underset{\begin{smallmatrix} Methyl \\ isocyanide \end{smallmatrix}}{\mathop{C{{H}_{3}}NC}}\,\xrightarrow[catalyst]{\operatorname{Re}duction}\underset{\begin{smallmatrix} N-methyl \\ methana\min e \end{smallmatrix}}{\mathop{{{H}_{3}}CNHC{{H}_{3}}}}\,\]
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