A) \[\frac{14}{9}\Omega \]
B) \[\frac{9}{14}\Omega \]
C) \[\frac{14}{3}\Omega \]
D) \[\frac{3}{14}\Omega \]
Correct Answer: C
Solution :
Key Idea: The circuit forms a balanced Wheatstone's bridge. The ratio of resistances in the opposite arms are \[\frac{3\Omega }{4\Omega }\]and \[\frac{6\Omega }{8\Omega }=\frac{3\Omega }{4\Omega }\]You need to login to perform this action.
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