A) 6 cm above the surface of water
B) 6 cm below the surface of water
C) 18 cm above the .surface of water
D) 32 cm above the surface of water
Correct Answer: D
Solution :
\[_{1}{{\mu }_{2}}=\frac{\text{Apparent depth}}{\text{Real depth}}=\frac{{{x}_{app}}}{{{x}_{r}}}\] Putting the numerical values, we have \[{{x}_{r}}=24\,cm,{{\,}_{1}}{{\mu }_{2}}=\frac{4}{3}\] \[\Rightarrow \] \[\frac{4}{3}=\frac{{{x}_{app}}}{24}\] \[\Rightarrow \] \[{{x}_{app}}=32\,cm\] Therefore, the object will appear 32 cm above the surface of the water.
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