A) 42
B) 47
C) 36
D) 34
Correct Answer: B
Solution :
Method used to form the series is 2ndterm = 1stterm\[\times \text{2}+\text{l}=\text{2}\times \text{2}+\text{1}=\text{5}\] 3rdterm = 2ndterm \[\times \text{2}+\text{l}=\text{5}\times \text{2}+\text{l}=11\]and 4thterm = 3rdterm \[\times \text{2}+\text{1}=11\times \text{2}+\text{l=}~\text{23}\] \[\therefore \]5thterm = 4thterm\[\times \text{2}+\text{1}=\text{23}\times \text{2}+\text{1=47}\]
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