AFMC AFMC Solved Paper-2000

  • question_answer
    If a planet consists of a satellite whose mass and radius are both half that of earth, acceleration due to gravity (g) at its surface should be:

    A)  29.4 m/s2           

    B)  19.6 m/s2

    C)   9.8 m/s2                             

    D)  4.9 m/s2

    Correct Answer: B

    Solution :

                                             From law of gravitation, the force of attraction acting on a body due to earth is \[F=\frac{G{{M}_{e}}m}{R_{e}^{2}}\]                                                                                                                                                                     ?(i) Also acceleration due to gravity g arises due to force F. From Newton's second law      \[F=mg\] Equating Eqs. (i) and (ii), we get \[mg=G\frac{{{M}_{e}}m}{R_{e}^{2}}\] \[\Rightarrow \]      \[g=\frac{G{{M}_{e}}}{R_{e}^{2}}\]  ?(iii) Here,      \[{{M}_{p}}=\frac{{{M}_{e}}}{2},{{R}_{p}}=\frac{{{R}_{e}}}{2}\] \[\therefore \]        \[{{g}_{p}}=\frac{G{{M}_{e}}/2}{{{({{R}_{e}}2)}^{2}}}\] Dividing Eqs. (iv) by (iii) , we have \[\frac{{{g}_{p}}}{g}=\frac{2G{{M}_{e}}}{R_{e}^{2}}\times \frac{R_{e}^{2}}{G{{M}_{e}}}\] \[{{g}_{p}}=2g\] \[{{g}_{p}}=2\times 9.8=19.6\,m/{{s}^{2}}\]


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