A) \[HP{{O}_{3}}\]
B) \[{{H}_{3}}P{{O}_{4}}\]
C) \[{{H}_{3}}P{{O}_{3}}\]
D) \[{{H}_{2}}{{P}_{2}}{{O}_{7}}\]
Correct Answer: A
Solution :
The oxidation number of central atom in its anhydride and acid is same In \[{{P}_{2}}{{O}_{5}},\]let oxidation number of \[P=x\] \[2x-10=0\] \[x=+5\] In \[{{H}_{3}}P{{O}_{4}}\]let oxidation number of P = y \[3+y-8=0\] \[y=+5\] As oxidation number of P in \[{{P}_{2}}{{O}_{5}}\]and \[{{H}_{3}}P{{O}_{4}}\]is same, \[{{P}_{2}}{{O}_{5}}\]is anhydride of \[{{H}_{3}}P{{O}_{4}}.\]
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