A) 0.7 L
B) 4.8 L
C) 1.4 L
D) 1.2 L
Correct Answer: A
Solution :
1 mole of substance \[\equiv \] its molecular mass \[\equiv 22.4L\] 32 g of \[{{O}_{2}}=22.4L\] (mol. mass of\[{{O}_{2}}=32\]) \[\Rightarrow \] 1 g \[{{O}_{2}}=\frac{22.4}{32}=0.7\,L\]
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