A) 4 A
B) 20 A
C) 10 A
D) 0.5 A
Correct Answer: B
Solution :
From Planck's theory \[\Delta E=hv\] where, v is frequency. \[\therefore \] \[\Delta E=\frac{hc}{\lambda }\] \[\Rightarrow \] \[\lambda =\frac{hc}{\Delta E}\] \[\therefore \] \[\lambda =\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{600\times 1.6\times {{10}^{-19}}}\] \[\approx 20\overset{\text{o}}{\mathop{\text{A}}}\,\]
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