A) Scattering is reduced at noon
B) Refraction of light is minimum at noon
C) Rays are incident almost normally
D) The sun is nearer to earth at noon
Correct Answer: C
Solution :
[c] The intensity of illumination is given by \[I=\frac{P\,\cos \theta }{{{r}^{2}}}\] Where P = power of the source r = distance between source and point \[\theta \] = angle of incidence When \[\theta \] = 0, I will be maximum. Hence, the rays from the sun are incident normally on the earth surface.
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