JEE Main & Advanced Physics Vectors Sample Paper Topic Test- Vectors

  • question_answer
    The vectors from origin to the points A and B are \[\vec{A}=3\hat{i}\,-6\hat{j}\,+2\hat{k}\] and \[\vec{B}=2\hat{i}+\,\hat{j}\,-2\hat{k}\] respectively. The area of the triangle OAB be

    A) \[\frac{5}{2}\,\sqrt{17}\,sq\,units\]

    B) \[\frac{2}{5}\,\sqrt{17}\,sq\,unit\]

    C) \[\frac{3}{5}\,\sqrt{17}\,sq\,unit\]           

    D) \[\frac{5}{3}\,\sqrt{17}\,sq\,unit\]

    Correct Answer: A

    Solution :

    [a] Given \[\overrightarrow{OA}=\,\vec{a}=\,3\hat{i}-6\hat{j}+2\hat{k}\] and
    \[\overrightarrow{OB}=\,\,\vec{b}=\,2\hat{i}+\hat{j}-2\hat{k}\]
    \[\therefore \]      \[\,(\vec{a}\times \vec{b})\,=\,\left| \,\begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    3 & -6 & 2  \\    2 & 1 & -2  \\ \end{matrix}\, \right|\]
    \[=\,(12-2)\,\hat{i}+(4+6)\hat{j}+\,(3+12)\,\hat{k}\]
    \[=10\hat{i}+\,10\hat{j}+15\hat{k}\]
    \[\Rightarrow \]   \[|\vec{a}\times \vec{b}|\,\,=\,\sqrt{{{10}^{2}}+\,{{10}^{2}}+{{15}^{2}}}\]
    \[=\,\sqrt{425}=\,5\sqrt{17}\]
    Area of \[\Delta OAB=\,\frac{1}{2}\,\,|\vec{a}\times \,\vec{b}|\,=\,\frac{5\sqrt{17}}{2}\,sq.\ unit\]


You need to login to perform this action.
You will be redirected in 3 sec spinner