JEE Main & Advanced Physics Transmission of Heat Sample Paper Topic Test - Transmission Of Heat

  • question_answer
    One end of a conducting rod is maintained at temperature \[50{}^\circ C\] and at the other end, ice is melting at \[0{}^\circ C\]. The rate of melting of ice is doubled if:

    A) the temperature is made \[200{}^\circ C\] and the area of cross-section of the rod is doubled

    B) the temperature is made \[100{}^\circ C\] and length of rod is made four times

    C) area of cross-section of rod is halved and length is doubled

    D) the temperature is made \[100{}^\circ C\] and the area of cross-section of rod and length both are doubled

    Correct Answer: D

    Solution :

    [d] Rate of melting of ice \[\propto \] rate of heat transfer and rate of heat transfer \[=\frac{\text{Temperature difference}}{\frac{l}{KA}}\] or rate of heat transfer \[\propto \frac{\text{(Temperature differnce)}}{l}A\]. If temperature difference A and l all are doubled, then obviously rate of heat transfer or rate of melting of ice will be doubled.


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