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JEE Main & Advanced Physics Thermodynamical Processes Sample Paper Topic Test - Thermodynamical Processes

  • question_answer
    743 J of heat energy is added to raise the temperature of 5 mole of an ideal gas by 2 K at constant pressure. How much heat energy is required to raise the temperature of the same mass of the gas by 2 K at constant volume?

    A) 826 J

    B) 743 J

    C) 660 J

    D)  620 J

    Correct Answer: C

    Solution :

    [c] For constant pressure process,
                       \[{{Q}_{1}}=n{{C}_{p}}dT-nRdT\]
                \[{{Q}_{2}}=n{{C}_{v}}dT=n({{C}_{p}}-R)dT=n{{C}_{p}}dT-nRdT\]
                            \[{{Q}_{2}}=743-5\times 8.3\times 2=660\,J\]


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