A) 1.30
B) 1.50
C) 1.67
D) 2.00
Correct Answer: B
Solution :
| [b] In adiabatic expansion, |
| \[p{{V}^{\gamma }}=\,\]constant put \[p=\,\frac{RT}{V}\] |
| \[\left( \frac{RT}{V} \right)\,{{V}^{\gamma }}=\,\,\text{constant}\,\,\] |
| \[T{{V}^{\gamma -1}}=\]constant or \[T\propto \,{{V}^{1-\gamma }}\] |
| \[\because \] \[T\propto \,\frac{1}{\sqrt{V}}\] |
| \[\therefore \] \[1-\gamma =-\frac{1}{2}\] |
| or \[\gamma =1+\frac{1}{2}\,=\frac{3}{2}\,=1.5\] |
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