A) 5472 kJ/mol
B) 48 kJ/mol
C) 684 kJ/mol
D) 4281 kJ/mol
Correct Answer: A
Solution :
| [a] Rise in temperature = 300 - 294 = 6 K |
| Heat given to the calorimeter |
| = Heat capacity \[\times \,\Delta T\]\[=8\times 6\] |
| = 48 kJ |
| Molar mass of octane \[({{C}_{8}}{{H}_{18}})=114\] |
| 1 g of octane gives = 48 kJ heat |
| 114 g of octane = 1 mol of octane gives |
| \[=48\times 114\,\,kJ\] |
| = 5472 kJ/mol |
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