A) - 13 kcal
B) + 13 kcal
C) - 14.4 kcal
D) - 13.7 kcal
Correct Answer: A
Solution :
| [a] \[{{H}^{+}}+O{{H}^{-}}\to {{H}_{2}}{{O}_{(l)}}\] | |
| \[\Delta H=-13.7kcal\] | ...(i) |
| \[CHC{{l}_{2}}COOH\to CHC{{l}_{2}}CO{{O}^{-}}+{{H}^{+}}\] | |
| \[\Delta H=0.7\,kcal\] | ...(ii) |
| \[CHC{{l}_{2}}COOH+O{{H}^{-}}\to CHC{{l}_{2}}CO{{O}^{-}}+{{H}_{2}}{{O}_{(l)}}\] | |
| \[\Delta H=?\] | |
| Adding Eq. (i) and (ii), \[\Delta H\] = - 13 kcal. | |
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