JEE Main & Advanced Chemistry Solutions / विलयन Sample Paper Topic Test - Solutions

  • question_answer
    Vapour pressure of \[CC{{l}_{4}}\] at \[{{25}^{o}}C\] is 143 mm of Hg. 0.5 gm of a non-volatile solute (mol. wt. = 65) is dissolved in 100 ml \[CC{{l}_{4}}.\] Find the vapour pressure of the solution (Density of \[CC{{l}_{4}}=1.54\,g.c{{m}^{3}}\])

    A) 141.93 mm

    B) 94.39 mm   

    C) 199.34 mm

    D) 143.99 mm

    Correct Answer: A

    Solution :

    [a]
    \[\frac{{{P}^{o}}-{{P}_{S}}}{{{P}^{o}}}=\frac{w\times M}{m\times W}\Rightarrow {{p}_{s}}={{p}^{o}}-{{p}^{o}}\left( \frac{w\times M}{m\times W} \right)\]
                \[=143-\frac{0.5\times 154}{65\times 158}\times 143\]
                \[\text{=143-1}\text{.07=141}\text{.93 mm}\text{.}\]


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