A) \[{{0}^{o}}\]
B) \[{{30}^{o}}\]
C) \[{{45}^{o}}\]
D) \[{{60}^{o}}\]
Correct Answer: C
Solution :
[c] \[C={{\sin }^{-1}}\left( \frac{1}{\mu } \right)={{\sin }^{-1}}\left( \frac{1}{2} \right)={{30}^{o}}\] |
\[\therefore \]Angle of the prism \[A={{30}^{o}}\] the ray trace it is path if it is incident normally as shown in fig. |
Now, \[{{r}_{2}}=0\] |
\[A={{r}_{1}}+{{r}_{2}}={{30}^{o}}\] |
Now, \[\mu =\frac{\sin {{i}_{l}}}{\sin {{r}_{l}}}\] |
or \[\sqrt{2}=\frac{\sin {{i}_{l}}}{\sin {{30}^{o}}}\] |
\[\therefore \] \[\sin {{i}_{l}}=\sqrt{2}\sin {{30}^{o}}=\frac{1}{\sqrt{2}}\] |
or \[\sin {{i}_{l}}=\sin {{45}^{o}}\] |
or \[{{i}_{l}}={{45}^{o}}\] |
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