JEE Main & Advanced Physics Ray Optics Sample Paper Topic Test - Refraction of Light Through Curved Surfaces

  • question_answer
    In the figure shown a point object O is placed in air. A spherical boundary of radius of curvature 1.0 m separates two media. AB is principal axis. The refractive index above AB is 1.6 and below AB is 2.0. The separation between the images formed due to refraction at spherical surface is:

    A) 12 m

    B)  20 m            

    C) 14 m

    D) 10 m

    Correct Answer: A

    Solution :

    For refraction by upper surface
    \[\frac{1.6}{{{V}_{1}}}-\frac{1}{-2}=\frac{1.6-1}{1}\Rightarrow \frac{1.6}{{{V}_{1}}}=0.6-0.5=0.1\]
    For refraction by lower surface \[\frac{2}{{{V}_{2}}}-\frac{1}{-2}=\frac{2-1}{1}\]
    Distance between images \[=(16-4)=12\,m\].

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