A) \[0.4\times {{10}^{-21}}kg-m/s\]
B) \[0.8\times {{10}^{-21}}kg-m/s\]
C) \[1.6\times {{10}^{-21}}kg-m/s\]
D) \[2.4\times {{10}^{-21}}kg-m/s\]
Correct Answer: C
Solution :
[c]| Applying refraction formula for curved surface \[\frac{{{\mu }_{2}}}{\upsilon }-\frac{{{\mu }_{1}}}{u}=\frac{{{\mu }_{2}}-{{\mu }_{1}}}{R}\] |
| \[\Rightarrow \] \[\frac{3}{2\upsilon }-\frac{1}{-10}=\frac{\frac{3}{2}-1}{+10}\] \[\Rightarrow \] \[\upsilon =-30\,cm\] |
| Magnification \[=\frac{{{h}_{i}}}{{{h}_{0}}}=\frac{{{\mu }_{1}}\upsilon }{{{\mu }_{2}}u}\] |
| \[\Rightarrow \] \[{{h}_{0}}=\frac{{{\mu }_{2}}u}{{{\mu }_{1}}\upsilon }{{h}_{i}}=\frac{\frac{3}{2}(-10)}{1\times (-30)}\times 10\,\,mm\] |
| \[\therefore \] \[{{h}_{0}}=5\,\,mm=\] radius of circle of \[{{e}^{-}}\] |
| \[\Rightarrow \] \[5\,mm=\frac{(m\upsilon )}{eB}\] \[\Rightarrow \] \[m\upsilon =5\times {{10}^{-3}}\times 1.6\times {{10}^{-19}}\times 2\,\,kg-m/s\] |
| \[\therefore \] Momentum \[=1.6\times {{10}^{-21}}\,kg-m/s\] |
You need to login to perform this action.
You will be redirected in
3 sec
