A) \[\frac{g}{19}\,m/{{\sec }^{2}}\]
B) \[\frac{9g}{11}\,m/{{\sec }^{2}}\]
C) \[0\,/{{\sec }^{2}}\]
D) \[g\,m/{{\sec }^{2}}\]
Correct Answer: B
Solution :
[b]\[N=m\,(g+a)\] |
\[N'=m\,(g-a)\] |
\[N'=\frac{10}{100}\times N\] |
\[m(g-a)=\frac{m(g+a)}{10}\] |
\[10g-10a=g+a\] |
\[9g=11a\,\,\Rightarrow \,\,a=\frac{9g}{11}\] |
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