question_answer

Two men of masses m and m/2 starts climbing up on two massless strings fixed at the ceiling with acceleration g and g/2 respectively. The ratio of tensions in the two strings will be:

A) 2 : 1

B) 4 : 1

C) 4 : 3

D) 8 : 3

Correct Answer: D

Solution :

[d] FBD of man of mass(m) FBD of man of mass (m/2)

\[{{T}_{1}}=mg+mg\]		\[{{T}_{2}}=\frac{m}{2}g+\frac{m}{2}.\frac{g}{2}\]
\[{{T}_{1}}=2mg\]		\[{{T}_{2}}=\frac{mg}{2}\left[ \frac{3}{2} \right]=\frac{3mg}{4}\]

\[\Rightarrow \]   \[{{T}_{1}}:{{T}_{2}}::8:3\]