A) 1/4
B) 1/2
C) 2/3
D) 1/3
Correct Answer: C
Solution :
| [c] At equilibrium, pressure is same, temp. and molecular weight do not change (given). |
| Using ideal gas eq. \[{{P}_{1}}{{V}_{1}}={{n}_{1}}R{{T}_{1}}\] |
| From above, \[\frac{V}{m}\] is constant, \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}};\] |
| Add 1 on both sides, we get \[\frac{{{V}_{1}}+{{V}_{2}}}{{{V}_{2}}}=\frac{{{m}_{1}}+{{m}_{2}}}{{{m}_{2}}}\] |
| \[\Rightarrow \] \[\frac{{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}}=\frac{2m}{m+2m}=\frac{2}{3}\] |
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