JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Chemical Equilibrium

  • question_answer
                For gaseous decomposition of\[PC{{l}_{5}}\], in a closed vessel the degree of dissociation \['\alpha '\], equilibrium pressure 'P' &\[{{K}_{p}}\] are related as

    A) \[\alpha =\sqrt{\frac{{{K}_{p}}}{{{K}_{p}}+P}}\]

    B) \[\alpha =\frac{1}{\sqrt{{{K}_{p}}+P}}\]

    C) \[\alpha =\sqrt{\frac{{{K}_{p}}+P}{{{K}_{p}}}}\]

    D) \[\alpha =\sqrt{{{K}_{p}}+P}\]

    Correct Answer: A


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