JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Chemical Equilibrium

  • question_answer
    Consider the reactions
    (i) \[CO(g)+{{H}_{2}}O(g)C{{O}_{2}}(g)+{{H}_{2}}(g)\]
    (ii) \[C{{H}_{4}}(g)+{{H}_{2}}O(g)CO(g)+3{{H}_{2}}(g)\]
    (iii) \[C{{H}_{4}}(g)+2{{H}_{2}}O(g)C{{O}_{2}}(g)+4{{H}_{2}}(g)\]
    Which of the following is correct?

    A) \[{{K}_{3}}={{K}_{1}}/{{K}_{2}}\]

    B) \[{{K}_{3}}=K_{1}^{1}/K_{2}^{3}\]

    C) \[{{K}_{3}}={{K}_{1}}.{{K}_{2}}\]   

    D) \[{{K}_{3}}={{K}_{1}}.\sqrt{{{K}_{2}}}\]

    Correct Answer: C

    Solution :

    [c] \[{{K}_{1}}=\frac{[C{{O}_{2}}][{{H}_{2}}]}{[CO][{{H}_{2}}O]},{{K}_{2}}=\frac{[CO]{{[{{H}_{2}}]}^{3}}}{[C{{H}_{4}}][{{H}_{2}}O]}\]
    \[{{K}_{3}}=\frac{[C{{O}_{2}}]{{[{{H}_{2}}]}^{4}}}{[C{{H}_{4}}]{{[{{H}_{2}}O]}^{2}}}\]
    \[\frac{{{K}_{1}}\times {{K}_{2}}}{{{K}_{3}}}=1\]
    \[{{K}_{1}}\times {{K}_{2}}={{K}_{3}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner