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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-9

  • question_answer
    A and B together can complete a job in 8 days. Both B and C, working alone can finish the same job in 12 days. A and B commence work on the job, and work for 4 days, where upon A leaves. B continues for 2 more days, and then he leaves too. C now starts working, and finishes the job. How many days did C require?

    A) 5                     

    B) 8

    C) 3                     

    D) 4

    Correct Answer: D

    Solution :

    Work done by A and B in first 6 days            = (A + B)'s 4 days' work +B?s 2 days' work \[=4\times \frac{1}{8}+\frac{2}{12}\] \[=\frac{1}{2}+\frac{1}{6}=\frac{3+1}{6}=\frac{4}{6}=\frac{2}{3}\] Remaining work             \[=1-\frac{2}{3}=\frac{1}{3}\] \[\therefore \]Time taken by C \[=\frac{1}{3}\times 12=4\] days


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