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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-6

  • question_answer
    If \[y:x=4:15,\] then the value of \[\left( \frac{x-y}{x+y} \right)\] is

    A)  \[\frac{11}{19}\]                                  

    B)  \[\frac{19}{11}\]

    C)  \[\frac{4}{11}\]            

    D)         \[\frac{15}{19}\]

    Correct Answer: A

    Solution :

     \[y:x=4:15\Rightarrow x:y=15:4\] By componendo and dividen- do. \[\frac{x-y}{x+y}=\frac{15-4}{15+4}=\frac{11}{19}\]


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