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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-3

  • question_answer
    Walking at \[\frac{3}{4}\] of his usual speed, a man is \[1\frac{1}{2}\]hours late. His usual time to cover the same distance, in hours, is

    A) \[4\frac{1}{2}\]               

    B) \[4\]

    C) \[5\frac{1}{2}\]             

    D)        \[5\]

    Correct Answer: A

    Solution :

     Time and speed are inversely proportional. \[\therefore \]\[\frac{4}{3}\]of usual time - usual time \[=\frac{3}{2}\] \[\Rightarrow \]\[\frac{1}{3}\times \]usual time\[=\frac{3}{2}\] \[\therefore \]Usual time\[=\frac{3\times 3}{2}=\frac{9}{2}\] \[=4\frac{1}{2}\]hours


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