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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-2

  • question_answer
    In the adjoining figure, ABCD is a quadrilateral in which AB is the longest side and CD is the shortest side, then:

    A)  \[\angle C>\angle A\]and\[\angle D<\angle B\]  

    B)  \[\angle C>\angle A\]and\[\angle B>\angle D\]

    C)  \[\angle C<\angle A\]and\[\angle D<\angle B\]

    D)  \[\angle C<\angle A\]and\[\angle D=\angle B\]

    Correct Answer: A

    Solution :

     Join \[AC\] and\[BD\]. As\[AB>AC\Rightarrow \angle ACB>\angle BAC\] Also\[AD>DC\Rightarrow \angle ACD>\angle CAD\] \[\therefore \]\[\angle ACB+\angle ACD>\angle BAC+\angle CAD\] \[\Rightarrow \]\[\angle C>\angle A\], similarly\[\angle D>\angle B\]


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