A) \[2\text{ }hrs.\]
B) \[2.5\text{ }hrs.\]
C) \[3\text{ }hrs.\]
D) \[3.5\text{ }hrs.\]
Correct Answer: A
Solution :
\[\therefore \] First tap in 10 minutes fills \[\frac{1}{4}\]part. \[\therefore \] First tap in 1 minutes fill \[\frac{1}{40}\] part. Another tap empty 1 part in 60 minutes \[\therefore \] In 1 minute it will empty \[\frac{1}{60}\] part. \[\therefore \] If both tap opened together then part filled in 1 minute \[=\frac{1}{40}-\frac{1}{60}=\frac{3-2}{120}=\frac{1}{120}\] \[\therefore \] Time taken by both pipes to fill the water tank \[=\frac{\frac{1}{1}}{120}=120\] minutes = 2 hours
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