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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-15

  • question_answer
    A man can walk uphill at the rate of \[2.5\text{ }kmph\] and downhill at the rate of\[3.25\text{ }kmph\]. If the total time required to walk a certain distance up the hill and return to the starting position is  \[4\text{ }hr\text{ }36\text{ }min,\] what is the distance he walked up the hill ?                    

    A) \[3.5\text{ }km\]                        

    B) \[4.5\text{ }km\]

    C) \[5.5\text{ }km\]                        

    D) \[6.5\text{ }km\]

    Correct Answer: D

    Solution :

    Let the distance he walked up the hill= d then, \[\frac{d}{2.5}+\frac{d}{3.25}=4+\frac{36}{60}\,hrs\] \[\Rightarrow \,\,\,\,\,\,d\left( \frac{3.25+2.5}{2.5\times 3.25} \right)=\frac{23}{5}\] \[\Rightarrow \,\,\,\,\,\,d\times \frac{5.75}{2.5\times 3.25}=\frac{23}{5}\] \[\Rightarrow \,\,\,d=\frac{23}{5}\times \frac{2.5\times 3.25}{5.75}\Rightarrow d=\]


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