A) \[20\text{ }sec\]
B) \[24.8\text{ }sec\]
C) \[28.8\text{ }sec\]
D) \[30\text{ }sec\]
Correct Answer: C
Solution :
Time taken by trains to cross each other \[=\frac{Sum\text{ }of\text{ }lengths\text{ }of\text{ }the\text{ }trains}{Relative\text{ }speed}\] \[=\frac{200+200}{(20+30)}\times \frac{18}{5}\] \[=\frac{400\times 18}{50\times 5}=\]| Short - cut Note: Relative speed in opposite direction \[=20+30=50\,kms/hr\] \[=50\times \frac{5}{18}m/s\] |
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