A) \[15\,km\]
B) \[8\,km\]
C) \[10\,km\]
D) \[14\,km\]
Correct Answer: C
Solution :
Let B be the initial point. \[\because \,\,\,ef=4\,km;\,\,\,\therefore \,CD=4\,km\] \[BD=(BC+CD)\] \[BD=(2+4)km=6km\Rightarrow AD=8km\] Applying Pythagoras Theorm in \[\Delta ADB\] \[A{{B}^{2}}=A{{D}^{2}}+B{{D}^{2}}\Rightarrow A{{B}^{2}}={{8}^{2}}+{{6}^{2}}\] \[AB=\sqrt{64+36}\Rightarrow AB=10\,km\] So, Arun is \[\] far away from his initial point.You need to login to perform this action.
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