A) \[1\]
B) \[\sqrt{2}\]
C) \[\sqrt{3}\]
D) \[2\]
Correct Answer: A
Solution :
\[\frac{1}{\left\{ (1+\sqrt{3})+\sqrt{2} \right\}}+\frac{1}{\left\{ (1+\sqrt{3})-\sqrt{2} \right\}}\] \[=\frac{1+\sqrt{3}-\sqrt{2}+1+\sqrt{3}+\sqrt{2}}{{{(1+\sqrt{3})}^{2}}-2}\] \[=\frac{2+2\sqrt{3}}{1+3+2\sqrt{3}-2}=\frac{2+2\sqrt{3}}{2+2\sqrt{3}}=\]
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