A) \[\frac{1}{7}\]
B) 7
C) 5
D) \[\frac{1}{5}\]
Correct Answer: B
Solution :
\[\tan \theta =\frac{4}{3}\] = then \[\frac{\sin \theta +\cos \theta }{\sin \theta -\cos \theta }\] = \[\frac{\cos \theta \left[ \frac{\sin \theta }{\cos \theta }+1 \right]}{\cos \theta \left[ \frac{\sin \theta }{\cos \theta }-1 \right]}=\frac{\tan \theta +1}{\tan \theta -1}\] = \[\frac{\frac{4}{3}+1}{\frac{4}{3}-1}=\]
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