A) 2A
B) \[90{}^\circ \text{ }+\frac{A}{2}\]
C) \[90{}^\circ -\frac{A}{2}\]
D) \[90{}^\circ +a\]
Correct Answer: B
Solution :
If the bisectors of angles B and C of a triangle meet at point I, then \[\angle BIC\] is equal to \[\mathbf{90}+\frac{\mathbf{A}}{\mathbf{2}}\]You need to login to perform this action.
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