A) 11
B) 10
C) 9
D) 8
Correct Answer: B
Solution :
\[\frac{x}{2}+\frac{y}{3}=4\Rightarrow 3x+2y=24\] ?(1) also \[\frac{2}{x}+\frac{3}{x}=1\Rightarrow 3x+2y=xy\] ?(2) From (1) and (2) we have \[\Rightarrow \] xy = 24 \[y=\frac{24}{x}\]Now from (1) \[3x+\frac{2\times 24}{x}=24\] \[\Rightarrow \,\,\,\,\,\,3{{x}^{2}}-24x+48=0\] ? (3) \[\begin{align} & \Rightarrow \,\,\,\,\,\,3{{(x-4)}^{2}}=0\Rightarrow x=4 \\ & y=\frac{24}{y}=\frac{24}{4}=6\Rightarrow x+y=4+6= \\ \end{align}\]You need to login to perform this action.
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