SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-5

  • question_answer
    If'-' stands for \['\div ',\text{ }'+'\] for \['\times ','\div \] for -', and \['\times '\] for\['+'\], which of the following is correct?

    A) \[30+10-12~8\times 12=46\]

    B) \[30\times 10-12\times 8+12~=48\]

    C) \[30\div ~10\times 12+8-12=44\]

    D) \[30-10+12\div ~8\times 12=40\]

    Correct Answer: D

    Solution :

    From the choices: [a] Replace (+, -,\[\div \], x) signs to (x,\[\div \],-,+) respectively We get, 30 x 10 \[\div \] 12 - 8 + 12 = 46 [Use 'BODMAS' rule] 30 x 5 \[\div \] 6 - 8 + 12 = 46 \[\Rightarrow \] 25 + 4 = 46 \[\Rightarrow \]29 \[\ne \] 46 [b] Replace (x, -, x, +) signs to (+,\[\div \], +, x) respectively We get, + 10 \[\div \] 12 + 8 x 12 = 48 [Use 'BODMAS' rule]  0.83 + 96 = 48 \[\Rightarrow \] 126.83 \[\ne \] 48 [c] Replace (\[\div \], x, +, -) signs to (-, +, x,\[\div \]) respectively We get, - 10 + 12 x 8 \[\div \] 12 = 44 [Use 'BODMAS' rule] - 10 + 8 = 44 \[\Rightarrow \] 28 \[\ne \] 44 [d] Replace (-, +,\[\div \], x) signs to (\[\div \], x, -, +) respectively We get, 30 \[\div \] 10 x 12 - 8 + 12 = 40 [Use 'BODMAS' rule] 3 x 12 + 4 = 40 \[\Rightarrow \] 36 + 4 = 40 \[\Rightarrow \] 40 = 40


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