SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-4

  • question_answer
    After arranging \[{{\left( 2.89 \right)}^{0.5}},2-{{\left( 0.5 \right)}^{2}},\] \[\sqrt{3}\]and \[\sqrt[3]{0.008}\] ln increasing order we have:

    A) \[2-{{(0.5)}^{2}},\sqrt{3},\sqrt[3]{0.008},{{(2.89)}^{0.5}}\]

    B) \[\sqrt[3]{0.008},{{(2.89)}^{0.5}},\sqrt{3},2-{{(0.5)}^{2}}\]

    C) \[\sqrt[3]{0.008},\sqrt{3},{{(2.89)}^{0.5}}2-{{(0.5)}^{2}}\]

    D) \[\sqrt{3},\sqrt[3]{0.008},2-{{(0.5)}^{2}},{{(2.89)}^{0.5}}\]

    Correct Answer: B

    Solution :

    \[~{{\left( 2.89 \right)}^{0.5}}= {{\left( 2.89 \right)}^{1/2}}= 1.7\] \[2 - {{\left( 0.5 \right)}^{2}}= 2 - 0.25 = 1.75\] \[\therefore \]\[\sqrt{3}\] =1.732 (approx.) \[\sqrt[3]{0.008}\] = 0.2 \[\therefore \] 0.2 < 1.7 < 1.732 < 1.75 \[\sqrt[\mathbf{3}]{\mathbf{0}.\mathbf{008}}\text{ }<\text{ }{{\left( \mathbf{2}.\mathbf{89} \right)}^{\mathbf{0}.\mathbf{5}}}<\text{ }\sqrt{\mathbf{3}\text{ }}<\text{ }\mathbf{2}-\text{ }{{\left( \mathbf{0}.\mathbf{5} \right)}^{\mathbf{2}}}\]


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