SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-4

  • question_answer
    If \[w=np+\frac{1}{2}~N{{X}^{2}}\]then, X =?

    A) \[\sqrt{\frac{wn-P}{2N}}\]                     

    B) \[\sqrt{\frac{2(w-nP)}{N}}\]

    C) \[\sqrt{\frac{nP-w}{2N}}\]                     

    D) None of these

    Correct Answer: B

    Solution :

    W = nP+\[\frac{1}{2}\]NX2 Or \[\frac{1}{2}N{{X}^{2}}=W-nP\,\,or\,\,{{X}^{2}}=\frac{2(W-nP)}{N}\] So, \[X=\sqrt{\frac{\mathbf{2}\left( \mathbf{W}\text{ }\text{ }\mathbf{nP} \right)}{\mathbf{N}}}\]


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