question_answer

In a circle, if PQ is the diameter of the circle and R is on the circumference of the circle, such that \[\angle PQR=30{}^\circ \] then \[\angle RPQ\] =?

A)  \[90{}^\circ \]             

B)  \[60{}^\circ \]

C) \[30{}^\circ \]              

D) \[45{}^\circ \]

Correct Answer: B

Solution :

 \[\therefore \] PQ is a diameter \[\Rightarrow \] \[\angle \]PRQ \[= 90{}^\circ  \left( An angle in a semicircle is 90{}^\circ  \right)\] \[\angle \]RPQ =\[180{}^\circ  - \left( 90{}^\circ  + 30{}^\circ  \right)\]= \[\]