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SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-1

  • question_answer
    If sin\[({{60}^{\circ }}-x)\]=cos (y = \[{{60}^{\circ }}\]) then the value of sin (x - y) is:

    A)  \[\frac{1}{\sqrt{2}}\]                

    B)  \[\frac{1}{2}\]

    C)  \[\frac{\sqrt{3}}{2}\]                

    D)  1

    Correct Answer: B

    Solution :

     Given that \[sin\left( 60{}^\circ -x \right)=cos(y+60{}^\circ )\] \[\Rightarrow \] \[\cos \left( {{90}^{{}^\circ }}-{{60}^{{}^\circ }}+x \right)=\cos \left( y+{{60}^{{}^\circ }} \right)\] \[\Rightarrow \]\[30{}^\circ +x=y+60{}^\circ \] \[\Rightarrow \] \[x-y=60{}^\circ -30{}^\circ \Rightarrow x-y=30{}^\circ \] \[\therefore sin\text{ }\left( xy \right)=sin30{}^\circ =\]


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