A) -3
B) 0
C) 3
D) None of the above
Correct Answer: A
Solution :
\[2x-3=0\Rightarrow x=\frac{3}{2}\] \[\therefore \,\,\,\,\,2{{\left( \frac{3}{2} \right)}^{3}}-5{{\left( \frac{3}{2} \right)}^{2}}+5\times \frac{3}{2}+k=0\] \[\frac{27}{4}-\frac{45}{4}+\frac{15}{2}+k=0;k=\mathbf{-3}\]You need to login to perform this action.
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