question_answer

A walks 10 m in front and 10 m to the right. Then, every time turning to his left, he walks 5, 15 and 15 m respectively. How far is he now from his starting point?

A)  5 m                 

B)  10 m

C)  20 m                           

D)  23 m

Correct Answer: A

Solution :

The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T). Since TS = OP + QR, so T lies in line with O. \[\therefore \] A's distance from the starting point O             \[=OT=(RS-PQ)\]             \[=(15-10)m\] \[=5\,m.\]