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SSC Sample Paper SSC CGL - Sample Paper-28

  • question_answer
    The perimeter of two squares are 24 cm and 32 cm. The perimeter (in cm) of a third square equal in area to the sum of the area of these square is

    A) 45                                

    B) 40       

    C) 32                                

    D) 48

    Correct Answer: B

    Solution :

    \[\because \] \[{{P}_{1}}=24\] \[\Rightarrow \]   \[{{a}_{1}}=6\,cm\] and       \[{{P}_{2}}=32\,cm\] \[\therefore \]    \[{{a}_{2}}=8\,cm\] \[\therefore \] Area of first square \[{{6}^{2}}=36\,c{{m}^{2}}\] and area of second square \[{{8}^{2}}=64\,c{{m}^{2}}\] \[\therefore \] Area of third square \[=36+64=100\,c{{m}^{2}}\] \[\Rightarrow \] Length of third square \[=10\,cm\] \[\Rightarrow \] Perimeter of third square \[=40\,cm\]


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