A) \[\frac{133}{90}\]
B) \[\frac{371}{90}\]
C) \[5\frac{219}{990}\]
D) \[5\frac{461}{990}\]
Correct Answer: D
Solution :
\[\because \] \[1.\overline{34}=\frac{134-1}{99}=\frac{133}{99}\] and \[4.\overline{12}=\frac{412-41}{90}\] \[=\frac{371}{90}\] \[\therefore \] \[1.\overline{34}+4.\overline{12}=\frac{133}{99}+\frac{371}{90}\] \[=\frac{1330+4081}{990}\] \[=\frac{5411}{990}=5\frac{461}{990}\]
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