A) Divisible by 3 but not divisible by 7
B) Divisible by 3 and 7 but not divisible by 11
C) Divisible by 2 and 7 but not divisible by 11
D) Divisible by 3, 7 and 11
Correct Answer: D
Solution :
.Given number is 222222. Here, sum of digits \[=2+2+2+2+2+2=12\] which is divisible by 3. So, given number is divisible by 3. Now, sum of odd terms of digits-Sum of even terms of digits \[=6-6=0\] it is divisible by 11. Since, in a number a digit repeated six times, then this number is divisible by 7, 11 and 13. \[\therefore \] The given number is divisible by 3, 7 and 11.
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