SSC Sample Paper SSC CGL - Sample Paper-27

  • question_answer
    If Z = 26, NET = 39, then NUT = ?

    A) 50                                

    B) 53

    C) 55                    

    D) 56

    Correct Answer: C

    Solution :

    Z = 26 (Position number in English Alphabet) \[\underset{14+5+20=39}{\overset{E}{\mathop{\overset{N}{\mathop{\downarrow }}\,\,\,\downarrow \,\,\overset{T}{\mathop{\downarrow }}\,}}}\,\]     Similarly,            \[\underset{14+21+20=\,\,55}{\mathop{\overset{N}{\mathop{\downarrow }}\,\,\,\overset{U}{\mathop{\downarrow }}\,\,\,\overset{T}{\mathop{\downarrow }}\,}}\,\] 


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