A) \[\sqrt{6}\]
B) \[\sqrt{3}\]
C) \[\sqrt{2}\]
D) 0
Correct Answer: D
Solution :
\[\frac{3\sqrt{2}}{\sqrt{6}+\sqrt{3}}-\frac{4\sqrt{3}}{\sqrt{6}+\sqrt{2}}+\frac{\sqrt{6}}{\sqrt{3}+\sqrt{2}}\] \[=\frac{3\sqrt{2}(\sqrt{6}-\sqrt{3})}{6-3}-\frac{4\sqrt{3}(\sqrt{6}-\sqrt{2})}{6-2}+\frac{\sqrt{6}(\sqrt{3}-\sqrt{2})}{3-2}\] \[=(\sqrt{12}-\sqrt{6})-(\sqrt{18}-\sqrt{6})+(\sqrt{18}-\sqrt{12})\] \[=2\sqrt{3}-\sqrt{6}-3\sqrt{2}+\sqrt{6}+3\sqrt{2}+2\sqrt{3}\] = 0
You need to login to perform this action.
You will be redirected in
3 sec
