A) + and \[\div ,\] 2 and 3
B) + and \[\div ,\] 2 and 4
C) + and \[\div ,\] 3 and 4
D) No interchange, 3 and 4
Correct Answer: A
Solution :
On interchanging +and -rand 2 and 3, we get the equation as \[(2+4)\div 3=2\] Or \[6\div 3=2\] Or 2 Which is true.You need to login to perform this action.
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